MATEMATIKA BILINGUAL Part 2
SPESIAL FOR RSBI and SSN Class for Schoolarship
Let's Try and View The Solution here
Question : 4 A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine
of a 120 metres long train running at 45 kmph in the same direction. In how much time
will the train pass the jogger?
Question : 5 A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?
Question : 4 A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine
of a 120 metres long train running at 45 kmph in the same direction. In how much time
will the train pass the jogger?
- 3.6 sec
- 18 sec
- 36 sec
- 72 sec
Correct Answer :
C
Explanation :
Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
= 36 x (5/18) m/sec
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
Time taken = 360/10 = 36 sec
Explanation :
Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
= 36 x (5/18) m/sec
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
Time taken = 360/10 = 36 sec
Question : 5 A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?
- 230 m
- 240 m
- 260 m
- 270 m
Correct Answer :
D
Explanation :
Speed = 72 x (5/18) = 20 m/sec. Time = 26 sec. Let the length of the train be x metres. Then, (x + 250)/26 = 20
x + 250 = 520
x = 270
Explanation :
Speed = 72 x (5/18) = 20 m/sec. Time = 26 sec. Let the length of the train be x metres. Then, (x + 250)/26 = 20
x + 250 = 520
x = 270
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